24x^2+36x-24=0

Solution for 24x^2+36x-24=0 equation:

24x^2+36x-24=0

a = 24; b = 36; c = -24;
Δ = b2-4ac
Δ = 362-4·24·(-24)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-60}{2*24}=\frac{-96}{48}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+60}{2*24}=\frac{24}{48}
=1/2
$